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2 years ago

PLEASE HELP FAST URGENT!!!

Mathematics

1 answer:

Sedbober [7]2 years ago

6 0

Answer:

A= Origen C= q1 B=Q2

Step-by-step explanation

your left-hand side is quadrant TWO Your top right-hand corner is Quadrant ONE and your second to the last one is left-hand side down Is Quadrant THREE last but not least is Quadrant FOUR. And the zero in the middle means ORIGEN.

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ELEN [110]

Answer:

I agree because 2 4/5 of 2 1/2 is 2 and there still is a half left

Step-by-step explanation:

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2 years ago

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The cost c (in dollars) for the care and maintenance of a horse and carriage is c= 15x 2000, where x is the number of rides? how

Semmy [17]

133.33
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3 years ago

What is the equation in point form of the line that passes through the point (2,6) and has a slope of 2

andriy [413]

point slope form

y-y1 = m(x-x1)

y-6 = 2(x-2)

from the answers shown, should the slope be 5?

then the answer would be

y-6 = 5(x-2)

Choice A

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3 years ago

PLEASE SOME ONE HELP ME IM DYING!!!!!

Afina-wow [57]

We know the area of the middle rectangle is 48 (length * width). removing that rectangle leaves us with two semicircles. you can combine those semicircles to be the equivalent of one circle. the area for a circle is r^2 * pi. we know the diameter is 4 because that is where we cut the semicircles. radius is half the diameter, so r is 2. 2^2 is 4, 4* pi is 12.56. add 12.56 (area of semicircles) with 48 (area of rectangle) and we get 60.56

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3 years ago

Please help!!

ZanzabumX [31]

The two linear equations in two variable is:

12 x + 3 y = 40

7 x - 4 y = 38

(a) For a system of equations in two Variable

a x + by = c

p x + q y = r

It will have unique solution , when

$\frac{a}{p}\neq \frac{b}{q}\neq\frac{c}{r}$

As, you can see that in the two equation Provided above

$\frac{12}{7}\neq \frac{3}{-4}\neq \frac{40}{38}$

So, we can say the system of equation given here has unique solution.

(b). If point (2.5, -3.4) satisfies both the equations, then it will be solution of the system of equation, otherwise not.

1. 12 x+3 y=40

2. 7 x-4 y=38

Substituting , x= 2.5 , and y= -3.4 in equation (1) and (2),

L.H.S of Equation (1)= 1 2 × 2.5 + 3 × (-3.4)

= 30 -10.20

= 19.80≠ R.H.S that is 40.

Similarly, L H S of equation (2)= 7 × (2.5) - 4 × (-3.4)

= 17.5 +13.6

= 31.1≠R HS that is 38

So, you can Write with 100 % confidence that point (2.5, -3.4) is not a solution of this system of the equation.

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2 years ago