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Julli [10]
2 years ago
7

Triangle HIJ is dilated by a scale factor of 55 to form triangle H'I'J'. Side I'J' measures 7575. What is the measure of side IJ

? (marking brainliest)
Mathematics
2 answers:
marusya05 [52]2 years ago
7 0
33344555778654444456777643322444566665
kvasek [131]2 years ago
3 0

Answer:

If triangle HIJ is dilated about the center of the triangle to create triangle H'I'J', dilated line A'B' will be parallel to AB.Option (D) is correct.

Given:

The options are as follows,

(A). be perpendicular to AB.

(B). lie on the same line as AB.

(C). shift four units to the left.

(D). be parallel to AB.

Step-by-step explanation:

If we dilate triangle HIJ then the dilated triangle  is bigger than the triangle HIJ.

The triangle HIJ is similar to triangle  to each other.

So the line  is parallel to side AB.

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Last week, a coral reef grew 19.8mm taller. How much did it grow in meters?
Oliga [24]

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Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
Let f be a differentiable function such that f(0) = -5 and f'(x) is less than or equal to 3 for all x. Of the following, which i
stepladder [879]
E) 2 
 Remember that the first derivative of a function is the slope of the function at any specified point. We've been told that f(0) = -5 and that f'(x) is always less than or equal to 3. So let's look at the available options and see what the average slope would have to be in order to get the specified value of f(2).
 A) -10: (-10 - -5)/(2 - 0) = -5/2 = -2.5
 B) -5: (-5 - -5)/(2 - 0) = 0/2 = 0
 C) 0: (0 - -5)/(2 - 0) = 5/2 = 2.5
 D) 1: (1 - -5)/(2 - 0) = 6/2 = 3
 E) 2: (2 - -5)/(2 - 0) = 7/2 = 3.5 
 Now taking into consideration the mean value theorem, the value of the function f'(x) has to have the value equal to the average slope between the two points at at least one point between the two given values. For options A, B, C, and D it's possible for f'(x) to return values that make that slope possible. However, for option E, the mean value theorem indicates that f'(x) has to have the value of 3.5 for at least 1 point between x=0 and x=2. And since we've been told that f'(x) is less than or equal to 3 for all possible values of x, that is in conflict and f(2) can not have the value of 2.
3 0
3 years ago
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