Answer:
y=-2x-3
Step-by-step explanation:
Since our equation is in standard form Ax+By=C we must first manipulate the equation so that we have it in the slope-intercept form such that y=mx+b. Therefore:
Therefore, our slope is 1/2 and our y-intercept is 2. Now in order to determine a perpendicular line to the one stated above we must then get the negative inverse of our slope meaning 
(negative reciprocal). Now we must use the point slope formula:
Where m is the slope, x1 is -2 and y1 is 1 (because of the ordered pair given). And so:
Therefore, the line that is perpendicular to -x+2y=4 is y=-2x-3.
<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
The is will be -<span>11b3</span><span> - 16b</span>2<span> + </span>4b<span> + </span><span>3</span>
Step-by-step explanation:
Since, y varies directly as x:
There is .82% chance they will have the same bdays
