Question

What is the equation of the line that passes through the point (-4, 2) and has a slope of -5/4?​

Answer 1

Answer:

y = -5/4 x - 3   is the slope-intercept form

5x + 4y = -12    is the standard form

Step-by-step explanation:

Use the point-slope form:  $y - y_{1} = m(x - x_{1})$

$(x_{1}, y_{1})$ = (-4, 2)

y - 2 = -5/4(x + 4)       Multiply by 4 to remove the fraction

4y - 8 = -5(x + 4)

4y - 8 = -5x - 20

4y = -5x - 12

y = -5/4 x - 3   is the slope-intercept form

5x + 4y = -12    is the standard form