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Neporo4naja [7]
3 years ago
10

How does the measure of the pink inscribed angle compare with the measure of the blue intercepted arc? How do you know?

Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

The pink angle is half the angle subtended by the blue arc.

Step-by-step explanation:

Given

See attachment for circle

Required

Compare the pink angle to the blue arc

Let the pink angle be x and the angle subtended by the blue arc be y.

So, we have:

x \to angle at circumference

y \to angle subtended by arc

The relationship between x and y is:

y =2x

Make x the subject

x = \frac{1}{2}y

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Courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100
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Well, drop 65 cents (the first 250 grams) to get 90 remaining cents. These are 900 additional grams. So, the mass is 0.25+0.9=1.15 kg.
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Please look at this multiple choice, thanks!
Nastasia [14]

Step-by-step explanation:

\frac{y - y1}{x - x1}  =  \frac{y2 - y1}{x2 - x1}

\frac{y - 0}{x - ( - 1)}  =  \frac{3 - 0}{1 - ( - 1)}

\frac{y}{x + 1}  =  \frac{3}{1 + 1}

\frac{y}{x + 1}  =  \frac{3}{2}

y =  \frac{3}{2} (x + 1)

y =  \frac{3}{2} x +  \frac{3}{2}

option B

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3 years ago
Solve the proportion!
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Suppose f(x)=x^2. what is the graph of g(x)=f(4x)?
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G(x)=f(4x)
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4 0
4 years ago
Read 2 more answers
A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
3 years ago
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