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3 years ago

The vertex of f(x) = 3x ^2+ 5x + 2 is a: minimum maximum none of these

Mathematics

1 answer:

timama [110]3 years ago

6 0

Answer:

minimum

Step-by-step explanation:

Given a quadratic in standard form f(x) = ax² + bx + c ( a ≠ 0 )

• If a > 0 then vertex is a minimum

• If a < 0 then vertex is a maximum

f(x) = 3x² + 5x + 2 ← is in standard form

with a = 3

Since a > 0 then vertex is a minimum

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An $42 item was marked down by 50%<br><br> what is the new cost of the item?

Nataly_w [17]

Answer:

New Cost of item is $\$ 21$

Step-by-step explanation:

Given:

Original Cost of item = $\$ 42$

Item was marked down by $50\%$

To Calculate Cost after $50\%$ marked down we need to multiply original cost by 50 and then divide by hundred.

Cost after marked down = $\frac{42 \times 50}{100}= \$21$

Now New cost of the item is calculated by Subtracting Cost after $50\%$ marked down by Original Cost of item.

New cost of the item = $\$ 42 - \$ 21 = \$21$

7 0

3 years ago

Lizzie has 30 coins that total $4.80. All of her coins are dimes, D, and quarters, Q. Algebraically determine how many of each t

Gnom [1K]

Lizzie has 18 dimes and 12 quarters

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that LIzzie has 30 coins

number of dimes + number of quarters = 30

d + q = 30 ---- eqn 1

Also given that the coins total $ 4.80

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

$d \times 0.10 + q \times 0.25 = 4.80$

0.1d + 0.25q = 4.8 ------ eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 30 - q ---- eqn 3

Substitute eqn 3 in eqn 2

0.1(30 - q) + 0.25q = 4.8

3 - 0.1q + 0.25q = 4.8

0.15q = 1.8

From eqn 3,

d = 30 - 12

Thus she has 18 dimes and 12 quarters

6 0

4 years ago

A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1

Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find : transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0

3 years ago

Read 2 more answers

A light bulb in Maya's house uses 9.4 watts of electric power each minute it is on. If the light bulb used a total of 6.58 watts

tamaranim1 [39]

Answer:

0.7 minute

Step-by-step explanation:

Given that each (1) minute a light use 9.4 watts.

So If the light bulb used a total of 6.58 watts, the minutes was on it is:

$\frac{The total watts used}{The watts used each minute}$

= $\frac{6.58}{9.4}$

= 0.7 minute

So the the minutes was on it is 0.7

Hope it will find you well!

4 0

3 years ago

The diameter of a sphere us 4 centimeters. which represents the volume of the sphere

Veronika [31]

Greetings and Happy Holidays!

The Formula for the Volume of a Sphere is: $V=\frac{4}{3}\pi r^3$

Input the value of the radius ( $\frac{d}{2}$ ):
$V=\frac{4}{3}\pi (2)^3$

Solve using the Order of Operations:
$V=\frac{4}{3}\pi (8)$

$V=\frac{4}{3}\pi \frac{8}{1}$

$V=\frac{32}{3}\pi$

The Answer Is:
$\boxed{V=33.510322}$

I hope this helped!
-Benjamin

5 0

3 years ago