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3 years ago

9

Having trouble with my functions homework plz can someone help

1 answer:

puteri [66]3 years ago

4 0

Answer:

$g(x) = \frac{ - 19}{3} x \: + 2$

I hope that is right

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Factorise the following algebraic expressions completely a. y4 −81 . x2 +10x +24

Ludmilka [50]

$y^4-81=(y^2-9)(y^2+9)=(y-3)(y+3)(y^2+9)\\\\
x^2 +10x +24 =x^2+10x+25-1=(x+5)^2-1=(x+5-1)(x+5+1)=(x+4)(x+6)$

3 0

3 years ago

Write an expression for the apparent nth term of the sequence 0, 3, 8, 15, 24

Finger [1]

S=i(n-1)+2*(n-1)+1 perhaps

6 0

3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

2 lines intersect and create VERTICAL angles. One of the angles measures (3n-28) degrees and the other angle measures 83 degrees

kykrilka [37]

Answer:

n=37

Step-by-step explanation:

Two lines intersect and create vertical angles.

The vertical angles are $(3n-28)^\circ$ and 83^\circ.$

We know that vertical angles (also called vertically opposite angles) are equal. Therefore:

$(3n-28)^\circ$ = 83^\circ.\\3n=28+83\\3n=111\\$Divide both sides by 3\\n=37$

8 0

3 years ago

Which of the following best describes the equation below?

DanielleElmas [232]

Answer:

B

Step-by-step explanation:

3x+33+6x=9x-33

9x+33=9x-33

33=-33

no solution

7 0

3 years ago