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KiRa [710]
3 years ago
15

St. Patrick's Day Problem Solving

Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

39,51 57

here is extra words

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Derivative of Y=cos^2(3x)
Black_prince [1.1K]
The derivative is -6sin(3x)
4 0
3 years ago
Find the perimeter of the following triangle.
Masteriza [31]

Answer:

If I did my math correctly, I'm pretty sure the answer is 3 1/36 yards.

Step-by-step explanation:

1. First, you have to turn them all into an improper fraction.

1 7/18 becomes 25/18

1 2/9 becomes 11/9

5/12 remains the same as it's already an improper fraction.

2. Find a common denominator, which is 36

25/18 becomes 50/36

11/9 becomes 44/36

5/12 becomes 15/36

3. Add them all together and you get 109/36

4. Turn it into a mixed number, and in this case, is 3 1/36

Solution is 3 1/36

5 0
3 years ago
Read 2 more answers
The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati
Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

                    \dfrac{24}{25}

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

i.e.

Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

6 0
3 years ago
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The sum of 18 and twice a number use n to rep<br> Repesent unknown number
Romashka-Z-Leto [24]

18+2n. For sure hope it helps

7 0
4 years ago
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Solve math problem number 2<br><br> -3y -7 = 2
Kisachek [45]
Add 7 to both sides.

-3y = 9

Divide -3 on both sides.

y = -3

Hope this helps!
6 0
3 years ago
Read 2 more answers
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