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Sophie [7]
3 years ago
14

Mark has 153 hot dogs and 171 hamburgers. He wants to put the same number of hot dogs and hamburgers on each tray. What is the g

reatest number of trays Mark can use to accomplish this?
Mathematics
2 answers:
drek231 [11]3 years ago
8 0

Answer:

Mark will use 153 no of trays to accomplish his task.

navik [9.2K]3 years ago
5 0

Answer: 153 trays

Step-by-step explanation:

hotdogs =153

Hamburger = 171

Mike is to put the same number of hamburger and hotdogs in each plate.

we assume that a whole number of each food is placed in each tray.

The maximum amount of trays will be determined by the minimum food which is hotdog, so, the hotdog is the constraint.

Mike will have to use 153 trays.

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4 years ago
I need help im not understanding how to do this
galina1969 [7]

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(c, b)

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Add the coordinates together and divide by 2

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3 0
2 years ago
Read 2 more answers
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pentagon [3]
It’s the one you are on
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3 years ago
What is the slope of the line that passes through the point 3,5 and -2,2
Nostrana [21]

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3/5

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8 0
3 years ago
A ball is projected in to the air. Its height at time t is given by the equation
Ksju [112]
The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

h=-16 t^{2} +60t+1
8=-16 t^{2} +60t+1
16 t^{2} -60t-1+8=0
16 t^{2} -60t+7=0

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) t^{2} = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}
t= \frac{60plus minus \sqrt{3600-448 } }{32}
t= \frac{60plus minus \sqrt{3152 } }{32}

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
t=  \frac{60+56.1426}{32} =3.63
and
t=  \frac{60-56.1426}{32} =.12

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.


3 0
3 years ago
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