The initial value equation is 
<h3>How to solve the initial value?</h3>
The equation is given as:

Where
Y(0) = 1
Subtract 2y from both sides in the equation

Rewrite as:

Integrate both sides of the equation

Multiply through by -2

Take the exponent of both sides

Next, we solve for C under the initial condition Y(0) = 1.
This gives

Evaluate
-2 + 3 = C
Solve for C
C = 1
Substitute C = 1 in 

Next, we solve for y

Hence, the initial value equation is 
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(x - 3)^2
(x - 3) * (x - 3)
x^2 - 3x
+ -3x + 9
x^2 - 6x + 9
Answer:
x∈R
Step-by-step explanation:
Identity property of multiplication