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zhenek [66]
3 years ago
5

Can anyone please help me on this?

Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

b

Step-by-step explanation:

ive done this beffore im a pro

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\begin{cases} -x+3y=9\\\\ y=\cfrac{2}{3}x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ -x+3y=9\implies 3y=9+x\implies \underline{3y-9=x} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting ont the 2nd equation}}{y=\cfrac{2}{3}(\underline{3y-9})\implies 3y=2(3y-9)}\implies 3y=6y-18\implies 18+3y=6y \\\\\\ 18=3y\implies \cfrac{18}{3}=y\implies \boxed{6=y}

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