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Eduardwww [97]
3 years ago
7

Using the digits 5, 6, 7, 8, 9 and repetition is allowed how many options are there to

Mathematics
1 answer:
just olya [345]3 years ago
8 0

Answer:

250 options to create an even number

375 options to create an odd number

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Please answer a little quiet<br>IT is urgent<br><br>.Factorize: 4(x-y)^2 -9 <br>.Evaluate : 1001×99​
Zarrin [17]

Answer:

1. (2x - 2y)² - 9

2. 99099

Step-by-step explanation:

We know the a+b formula :

(a-b)² = a² - 2ab + b²

1. 4(x-y)^2 -9

4(x² - 2xy + y²) - 9

4x² - 8xy + 4y² - 9

(2x - 2y)² - 9

2. 1001 × 99​

= 99099

1001

×  99                                                                                                                           ----------

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3 0
3 years ago
12ad^3 and which terms are like terms?<br> 15a^3d<br> 12d^3<br> 3ad^3<br> 10ad
storchak [24]
Like terms are terms with the exact same variables, and the exact same degree of each variable...simply put, the exponents of each variable have to be exactly the same.
The given term 12 ad³ has variables a and d. a has a degree of 1 and d has a degree of 3.
The term 3ad³ has the same variables and the same degree, and is therefore the like term.
8 0
3 years ago
X(x+1)(x+2)(x+3)=24
enyata [817]

Answer:1(1+1)(1+2)(1+3)

Step-by-step explanation:

5 0
3 years ago
What is the first step to solve the equation 9h-31=99?
pishuonlain [190]

Add 31 to both sides which will give you

9h = 130

4 0
3 years ago
Read 2 more answers
A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
Drupady [299]

Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

# The mass of iron is 1225 g

Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

∵ Density = mass/volume

∵ The mass = 23.6 g

∵ The volume = 150 cm³

∴ The density = 23.6/150 = 59/375 ≅ 0.157 g/cm³

* The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The density of mercury is 13.6 g/cm³ at 23 C°

- A container can hold 3.2 g of mercury at this temperature

∵ Density = mass/volume

∵ The mass = 3.2 g

∵ The density = 13.6 g/cm³

∴ 13.6 = 3.2/volume

- By using cross multiplication

∴ The volume = 3.2/13.6 = 4/17 cm³

* The volume of the container is 4/17 ≅ 0.235 cm³

# The density of the iron is 4.9 g/cm³

- The beaker has a volume 250 ml

∵ Density = mass/volume

∵ The ml = cm³

∴ The volume of the beaker is 250 cm³

∵ The density = 4.9 g/cm³

∴ 4.9 = mass/250

- Multiply both sides by 250

∴ mass = 1225 g

* The mass of iron is 1225 g

7 0
3 years ago
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