Answer:
49 eggs.
Step-by-step explanation:
The formula for Margin of Error =
z × standard deviation/√number of samples
z = z score of 98% confidence interval = 2.326
Margin of Error = Half a day = 1/2day = 0.5 day
Standard deviation = 1.5 days
Number of samples = number of eggs he needs to sample = unknown.
Imputing these above values into the formula
Margin of Error = z × standard deviation/√number of samples
0.5 = 2.326 × 1.5/√n
Cross Multiply
0.5 × √n = 2.326 × 1.5
√n = 2.326 × 1.5/0.5
√n = 3.489/0.5
√n = 6.978
Square both sides
(√n)² = 6.978²
n = 48.692484
n ≈ Approximately to the nearest whole number = 49
Therefore, the number of eggs he needs to sample to create the desired interval is approximately to the nearest whole number 49 eggs
Answer:
6
Step-by-step explanation:
-3 -1 +2 +8 = -4+10 = 6
Answer:
Is there ever a time when the X is the same? if so, then it is not a function, if the X is never the same, it is a function.
Step-by-step explanation:
I'm sorry, but I'm to lazy to do the math right now, but maybe this will help?
Using the lognormal and the binomial distributions, it is found that:
- The 90th percentile of this distribution is of 136 dB.
- There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.
- There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.
In a <em>lognormal </em>distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of
.
- The standard deviation is of

Question 1:
The 90th percentile is X when Z has a p-value of 0.9, hence <u>X when Z = 1.28.</u>






The 90th percentile of this distribution is of 136 dB.
Question 2:
The probability is the <u>p-value of Z when X = 150</u>, hence:



has a p-value of 0.9147.
There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.
Question 3:
10 signals, hence, the binomial distribution is used.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
For this problem, we have that
, and we want to find P(X = 6), then:


There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.
You can learn more about the binomial distribution at brainly.com/question/24863377