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Aloiza [94]
3 years ago
6

If x+ 1/x=8, find x^2+ 1/x^2​

Mathematics
1 answer:
Paraphin [41]3 years ago
6 0

Dude please give me brainliest please :)
Also here’s the answer

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Give the function y=-5x+12, what is the output (y) when the input, x=-2?
artcher [175]

Answer:

y=22

Step-by-step explanation:

y=-5(-2)+12

y=10+12

y=22

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Find the reciprocal of the number.<br><br> 57
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Answer:

\frac{1}{57}

Step-by-step explanation:

The reciprocal of a number is 1 / the number,

so the reciprocal of x is \frac{1}{x}.

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What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y
san4es73 [151]

Equivalent expressions are expressions that have the same value, and can be used interchangeably.

The result of the sum 2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) is 4x\sqrt[3]{2y}  + 8x^2y\sqrt[3]{2y^2})

The expression is given as:

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5})

Rewrite the expression as:

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y})  + 4 (\sqrt[3]{3^3 \times 2x^6y^5})

Evaluate the roots

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y})  + 4 (3x^2y\sqrt[3]{2y^2})

Open the brackets

2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y}  + 12x^2y\sqrt[3]{2y^2})

The above expression cannot be further simplified.

Hence, the result of the sum 2 (\sqrt[3]{16x^3y})  + 4 (\sqrt[3]{54x^6y^5}) is 4x\sqrt[3]{2y}  + 8x^2y\sqrt[3]{2y^2})

Read more about equivalent expressions at:

brainly.com/question/2972832

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Find the percent of markup. Round to the nearest tenth.<br> $33.50 to $63.00
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88.1% is the markup. Hope this helps!
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