Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer and Step-by-step explanation:
The way you complete this is by taking each points x and y and applying the translation. In this case the translation is x-7 and y+1.
Q's x and y are 1 , 1
R's x and y are 1 , 5
T's x and y are 5 , 1
S's x and y are 5 , 5
Now what you do is use the translation on all of these values.
Q's x and y turns into -6 , 2 (subtracted 7 to the 1 and added 1 to the 1)
R's x and y turns into -6 , 6
T's x and y are -2 , 2
S's x and y are -2 , 6
You can then plot the points on the graph and connect the lines to complete the reflection.
Hope this helps ! !
<3
Answer:
- 5x²-2x+7+2x²+6x-9
- 5x²+2x²-2x+6x+7-9
- 7x²+4x-2
so, 7x²+4x-2 is yr answer.
hope it helps.
<h3>stay safe healthy and happy.</h3>
Answer:
The number of hours.
Step-by-step explanation:
The dependent variable is what you are mesuaring.
