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kherson [118]
2 years ago
9

Four students wrote sequences during math class.

Mathematics
2 answers:
N76 [4]2 years ago
6 0
Doug because his sequence follows a rule of multiplying by -1/2 Hope I got it right for your sake.
AleksAgata [21]2 years ago
4 0

Answer:

Doug wrote geometric sequence.

Step-by-step explanation:

a geometric sequence is where we get common ratio between consecutive terms

\text{common ratio}=\frac{a_2}{a_1}

In case of Andre:

On substituting the values so as to find common ratio is

\frac{\frac{3}{8}}{\frac{3}{4}}=\frac{-1}{2}

\frac{\frac{-3}{16}}{\frac{3}{8}}=\frac{-1}{2}

\frac{\frac{-3}{32}}{\frac{-3}{16}}=\frac{1}{2}

Andre did not write a geometric sequence.

In case of Brenda:

On substituting the values so as to find common ratio is

\frac{\frac{-3}{8}}{\frac{3}{5}}=\frac{-5}{8}

\frac{\frac{3}{16}}{\frac{-3}{8}}=\frac{-1}{2}

\frac{\frac{3}{32}}{\frac{3}{16}}=\frac{1}{2}

Brenda did not write a geometric sequence.

In case of Camille

On substituting the values so as to find common ratio is

\frac{\frac{3}{8}}{\frac{3}{4}}=\frac{1}{2}

\frac{\frac{-3}{16}}{\frac{3}{8}}=\frac{-1}{2}

\frac{\frac{-3}{32}}{\frac{-3}{16}}=2

Camille did not write a geometric sequence.

In case of Doug:

On substituting the values so as to find common ratio is

\frac{\frac{-3}{8}}{\frac{3}{4}}=\frac{-1}{2}

\frac{\frac{3}{16}}{\frac{-3}{8}}=\frac{-1}{2}

\frac{\frac{-3}{32}}{\frac{3}{16}}=\frac{-1}{2}

Doug wrote a geometric sequence.

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