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sergey [27]
3 years ago
15

Iteration question please help

Mathematics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

Ur answer is 2/8

Hope this helps u

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Write a word phrase for each algebraic expression
Alex73 [517]
Y/5.....the quotient of y and 5

14.1 - w....the difference of 14.1 and w

9n + 1....the product of 9 and a number (n), increased by 1

(z/8) - 9.....9 less then the quotient of z and 8

15 - (1.5/d) ....15 decreased by the quotient of 1.5 and a number (d)


3 0
3 years ago
What is the following quotient
gregori [183]

Answer:

last one ! hope it's right :)

Step-by-step explanation:

4 0
3 years ago
Kara and Joe are planting wildflowers in their backyard flower garden. They bought a package of seeds with eight daisy seeds, th
Diano4ka-milaya [45]

Answer:

B. 12/33

Step-by-step explanation:

Since there are 12 bluebonnets and 30 seeds in total, the ratio will be 12:33.

4 0
3 years ago
Read 2 more answers
Simplify the expression (2 + 6i)(4 - 2i)
babymother [125]

Your answer would turn out to be

D. 20+21i

4 0
3 years ago
Suppose you want to count the number of​ four-letter passwords that can be formed using the letters in the word NUMBER. The four
WITCHER [35]

Answer:

D.The password must not follow order matter

Step-by-step explanation:

We are given that suppose you want to count the number of four letters password that can be formed using the letters in the word NUMBER.

We are given that all letters in the password must be all different .There is no nothing saying about order so we can make combination without order .

We have to find the number of 4- letter password that can be formed using letters in the word NUMBER.

By using Permutation formula we find the number of 4- letters password that can be formed by using the letters N,M,B,U,E,R.

Permutation formula : The number of arrangements when taken r objects at a time out of n objects

=\frac{n!}{(n-r)!}

Total letters in word NUMBER=N,U,M,B,E,R=6

n=6,r=4

Therefore, the number of arrangements  can be made from 6 letters when 4 letters taken at a time =\frac{6!}{(6-4)!}

The number of selection can be made from 6 letters when 4 letters taken at a time =\frac{6!}{(6-4)!}

The number of selection can be made from 6 letters when 4 letters taken at a time =\frac{6\times5\times 4\times3 \times 2!}{ 2!}

n!=n(n-1)(n-2)(n-3)...........3\cdot.2\cdot.1

The number of selection can be made from 6 letters when 4 letters taken at a time =360

Option D is correct.

Answer : D.The password must not follow order matter

6 0
4 years ago
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