The base of a triangle is 5/8 ft. The height is 1/3 ft.

Write the equation of the line shown in the graph in slope intercept form

AnnZ [28]

Answer:

y= 4x +3

Step-by-step explanation:

slope= rise over run

y-intercept = where the line hits the y axis

4 0

3 years ago

The gear is one of the oldest mechanical devices. It has been used since ancient times for its ability to increase or decrease r

eduard

The large gear attached to the pedals connected to the smaller gear

attached to the wheel allows the bicycle to travel further per rotation.

Correct responses:

Part A: Approximately 10.47 inches

Part B: 300°The d

Part C: Approximately 125.66 inches

Part D: The distance traveled increases by approximately 62.83 inches

<h3 /><h3>Methods used to calculate the above values</h3>

Given:

The radius of the large central gear, <em>r</em> = 4 inches

Radius of the small gear = 2 inches

Part A:

The distance travelled by the larger gear when the angle of rotation is 150° is given as follows;

$\displaystyle Distance \ travelled \ by \ larger \ gear = \mathbf{\frac{150^{\circ}}{360^{\circ}} \times 2 \times \pi \times 4 \, inches} = \frac{10}{3} \cdot \pi \ inches$

$\displaystyle Distance \ traveled \ by \ the \ outer \ edge = \frac{10}{3} \cdot \pi \ inches \approx \underline{ 10.47 \ inches}$

Part B:

When the small gear travels the same linear distance as the large gear in part A, we have;

$\displaystyle Degree \ of \ rotation = \frac{\frac{10}{3} \cdot \pi }{2 \times \pi \times 2 } \times 360^{\circ}= 300^{\circ}$

The degree of rotation of the small gear = <u>300°</u>

Part C:

The distance travelled, <em>C</em>, by a single rotation of the large gear is given as follows;

C = 2 × π × 4 inches = 8·π inches

The degree of rotation of the smaller gear following one rotation of the large gear is therefore;

$Degree \ of \ rotation = \displaystyle \frac{8\cdot \pi \ inches}{4 \cdot \pi \ inches } \times 360^{\circ} = \mathbf{ 720^{\circ}}$

720° = 2 × 360°

1 complete rotation is equivalent to 360°.

Therefore'

720° is equivalent to two complete rotation.

Therefore, the smaller gear and the wheel rotates twice for each rotation of the large gear

The distance the bicycle travels = 2 × The circumference of the wheel

Therefore;

Distance traveled by the bicycle = 2 × 2 × π × 10 inches = 40·π inches

Distance traveled by the bicycle = 40·π inches ≈ <u>125.66 inches</u>

Part D:

If the radius of the small gear is 1.5 inches and the radius of the large gear is 4.5 inches, we have;

Number of rotation of the small gear for each rotation of the large gear = 3 rotations

Therefore, number of rotation of the wheel = 3

Distance the bicycle travels = 3 × 2 × π × 10 inches = 60·π inches

The difference in distance traveled = 60·π inches - 40·π inches = 20·π inches

The distance traveled by the bicycle increases by 20·π inches ≈ <u>62.83 inches</u>

Learn more about gear transmission here:

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8 0

3 years ago

If it is 6:08 what time will it be in 45 minutes?

saw5 [17]

6:08 + 45 minutes = 6:53

8 0

3 years ago

Read 2 more answers

2(y + 5) <br> use the distributive property to expand expressions.

marta [7]

Answer:

2(y+5)

Step-by-step explanation:

= 2y+10 simple multiplication method

3 0

3 years ago

Read 2 more answers

HELP “The vertical supports in this truss bridge are built so that

ElenaW [278]

Answer:

The statement that is not true is;

c) m∠ABO = m∠ODC

Step-by-step explanation:

With the assumption that the lengths AO, and OD are equal, we have that in ΔABO and ΔOCD, the following sides are corresponding sides;

Segment AO on ΔABO is a corresponding side to segment OD on ΔOCD

Vertices B and C on ΔABO and ΔOCD are corresponding vertices

Therefore;

Segments AB and OB on ΔABO are corresponding sides to segments OC and OD on ΔOCD respectively

Therefore, ∠ABO on ΔABO is the corresponding angle to ∠OCD on ΔOCD

Given that ΔABO ≅ ΔOCD, we have that ∠ABO ≅ ∠OCD

Therefore;

m∠ABO = m∠OCD by definition of congruency

5 0

3 years ago