Answer:
Written in C++
void number(int n){
if(n%2 == 0)
cout<<2 * n;
else
cout<<5 * n;
}
Explanation:
The programming language is not stated.
However, I answered using C++
This line defines the function as void
void number(int n){
This line checks if the number is even
if(n%2 == 0)
If yes, it doubles the number and prints the output
cout<<2 * n;
If otherwise,
else
It multiplies the number by 5 and prints the output
cout<<5 * n;
}
To call the function from main, use:
number(n);
Note than n must be declared as integer
See attachment
Answer:
nums = []
while True:
in = input()
if in:
nums.append(in)
else:
break
if nums:
avg = sum(nums) / len(nums)
for i in range(len(nums)):
if nums[i] == avg:
print(f"index: {i+1}")
print(nums[i])
else:
print(-1) # if there aren't any values in nums
Explanation:
Assuming that you are coding in Python 3x. The last 'else' statement is an edge case that you might want to consider, I don't know what you want to put there, but I'm just going to leave it as -1.
There are 0.5 strides in one girth
so 4.5 strides will be equal to 9 girth
hope it helps
Answer:
The Matlab code is as given in the explanation, paste the code in the new script file, save it and run.
Explanation:
The code is as follows
Code:
<em>%% Initialization of the code</em>
<em>% The code takes an array of six AIS scores of the form [AIS1 AIS2 AIS3</em>
<em>% AIS4 AIS5 AIS6] of order 1x6.</em>
<em>AIS=input('Please enter the AIS array of the form [AIS1 AIS2 AIS3 AIS4 AIS5 AIS6]');%taking input of the array</em>
<em>AISs=sort(AIS,'descend');%sorting the array in the descending order</em>
<em>iss=(AISs(1,1)^2)+(AISs(1,2)^2)+(AISs(1,3)^2);%Calculating the ISS</em>
<em>disp(['The injury severity score (ISS) for the entered array is ', num2str(iss)])%Displaying the output</em>
Output:
<u><em>Please enter the AIS array of the form [AIS1 AIS2 AIS3 AIS4 AIS5 AIS6][3 0 4 5 3 0];</em></u>
<u><em>The injury severity score (ISS) for the entered array is 50</em></u>
<u><em /></u>
Answer:
The right approach is Option b (volume testing).
Explanation:
- A non-functional trial that has been conducted throughout a results evaluation where even a large amount of information becomes accessible to something like the program, would be determined as Volume testing.
- The application functionality has been analyzed by determining the maximum volume throughout the database.
Other options are not related to the given query. So the above is the right response.
