The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle (x,y):

Plugging in points A and B into distance formula, then setting them equal to each other gives:

Right away we can cancel out the x terms leaving:

Expand Left side and Solve for y:


Plug in points B and C as before:

Here we can cancel the y-terms.
Expand and solve for x:



Therefore the center of the circle is the point (6,3)
Answer:
The polynomial will be P(x) = - 5 (x + 2)²(x - 3)
Step-by-step explanation:
The degree of the polynomial P(x) is 3 and it has zeros at x = - 2 with multiplicity 2 and at x = 3 with multiplicity 1.
Therefore, (x + 2)² and (x - 3) are the factors of the equation.
Let the polynomial is
P(x) = a(x + 2)²(x - 3) ........... (1)
Now, the polynomial passes through the point (2,80).
So, from equation (1) we gat,
80 = a(4)²(-1)
⇒ a = - 5
Therefore, the polynomial will be P(x) = - 5 (x + 2)²(x - 3) (Answer)
Answer:
Third option.
Step-by-step explanation:
The triangles below are similar, because they have congruent corresponding angles.
Angle N is 105 degrees and angle Q is 105 degrees.
Since you have an equation equal to both x and y, you can either substitute the equation equal to x for x or the equation equal to y for y.
x=y-1
y=4-2x
I would substitute the y in using 4-2x
x=(4-2x)-1
x=3-2x
3x=3
x=1
Then plug in x and solve for y
1=y-1
2=y