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finlep [7]
3 years ago
13

Define “implied threat” in your own words.

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0
Implied threat means Harmful intentions
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Roma selects cards from a standard of 52 cards. Once a card is selected, it is not replaced. Find the probability of each outcom
meriva

Given:

A card is selected randomly from a standard deck of 52 cards.

To find:

The probability of each outcome.

a. a king of heart

b. a queen of spades

c. an ace of flower

d. an ace of diamond​

Solution:

In a standard deck of 52 cards.

Total number of cards = 52

13 cards of each suit (heart, diamond, club, spade).

13 cards are Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King.

a. We need to find the probability of getting a king of heart.

Number of king of heart = 1

P(\text{a king of heart})=\dfrac{\text{Number of king of heart}}{\text{Total cards}}

P(\text{a king of heart})=\dfrac{1}{52}

b. We need to find the probability of getting a queen of spades.

Number of queen of spades = 1

P(\text{a queen of spades})=\dfrac{\text{Number of queen of spades}}{\text{Total cards}}

P(\text{a queen of spades})=\dfrac{1}{52}

c. We need to find the probability of getting an ace of flower (spades).

Number of ace of flower = 1

P(\text{an ace of flower})=\dfrac{\text{Number of ace of flower}}{\text{Total cards}}

P(\text{an ace of flower})=\dfrac{1}{52}

d. We need to find the probability of getting an ace of diamond​.

Number of ace of diamond​ = 1

P(\text{an ace of diamond​})=\dfrac{\text{Number of ace of diamond​}}{\text{Total cards}}

P(\text{an ace of diamond​})=\dfrac{1}{52}

Therefore, the required probabilities for each parts are:

(a) \dfrac{1}{52}

(b) \dfrac{1}{52}

(c) \dfrac{1}{52}

(d) \dfrac{1}{52}

4 0
3 years ago
Jackie bought a game that contained a ball and 10 jacks. The ball had a radius of 2 inches. What is the volume of the ball? Roun
defon
V = 1¹/₃πr³
V = 1¹/₃(3.14)(2)³
V = 1¹/₃(3.14)(8)
V = 1¹/₃(25.12)
V ≈ 33.493 in³
4 0
4 years ago
45-8÷(4-2)×9+10 how do you do this
kati45 [8]
Do PEMDAS 

so do 4-2 which is 2

2 x 9 is 18 x 10 is 180

45 - 8 is 37 

180 divided by 37 is 4.9
6 0
4 years ago
Read 2 more answers
1) solve for w: 3w - 10 = 4w + 5<br> 2) solve for t:6 -2t &gt;18
Gre4nikov [31]
Problem # 1
 3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)

problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12 
(-1) (-2t) >  12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
 t >  -6     (t is greater then negative 6)

 
5 0
4 years ago
Find the value of x.  Round to nearest hundredth if necessary.
anyanavicka [17]
The side on the front of 30° is 1/2 of hypytenuse
Then 1/2 of 4=2 and the ather side with theorem of pytagore is squares root of(4^2-2^2)=sq .root of 12
This side(square root of 12) is 1/2 of hypotenuse then
Hypotenuse is 2*square root 12
X^2=(2*sq .root12)^2 -(square root 12)^2
X^2=48-12=36
X=6
6 0
4 years ago
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