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anygoal [31]
3 years ago
10

What is the gcf of 16,100

Mathematics
1 answer:
Kisachek [45]3 years ago
3 0
The Greatest Common Factor of 16, 100 is 4.
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5x+18/8 = x/4 <br> Solve for x
ollegr [7]

Answer: x= -9/19

Step-by-step explanation:

5x+18/8=x/4

5x+ 9/4=x/4

5x+9/4-9/4=x/4-9/4

5x= x-9/4

5x(4)=x-9/4(4)

20x=x-9

20x-x=x-9-x

19x=-9

19x/19=-9/19

x=-9/19

8 0
3 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state
Rus_ich [418]

Answer:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The proportion estimated would be:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

3 0
3 years ago
Read 2 more answers
Matrix A = [6 -12 4 8]. What is matrix X if 1/2x=A?
Step2247 [10]

Answer:

X = \left[\begin{array}{cccc}12&-24&8&16\end{array}\right]

Step-by-step explanation:

A matrix is given by

A = \left[\begin{array}{cccc}6&-12&4&8\end{array}\right]

Now, we have to find the matrix X if \frac{1}{2} X = A

⇒ X = 2A

Now, multiplication of a constant with a matrix means multiplication with that constant with all the terms of the matrix.

So, X = \left[\begin{array}{cccc}6 \times 2&-12 \times 2&4 \times 2&8 \times 2\end{array}\right]

⇒ X = \left[\begin{array}{cccc}12&-24&8&16\end{array}\right] (Answer)

4 0
4 years ago
Read 2 more answers
Which of the following equations is modeled by the graph.
Sergio [31]

Answer:

a = 50t

Step-by-step explanation:

The graph goes through (0,0) so the y intercept is 0

a=5t

a=50t

a=50 + t    not it

a=10t ​

The slope is  y/x since the y intercept is 0

m = 50/1 = 50

The equation for the line is

y = 50x+0

y = 50x

Using the variables given

a = 50t

5 0
3 years ago
Write each expression in terms of sines and/or cosines and then simplify.
Sedaia [141]
Tan(x)= sin(x)/cos(x), therefore, substitute sin(x)/cos(x) in the expression:
=(cos(x)(sin(x)/cos(x))-1)/cos^2(x)
simplify the 2 cos(x):
=(sin(x)-1)/cos^2(x)
Sin^2(x)+ cos^2(x)=1, sin^2(x)-1=- cos^2(x), substitute in the expression:
= -cos^2(x)/cos^2(x)= -1
8 0
3 years ago
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