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zhannawk [14.2K]
3 years ago
10

A student is assigned the task of placing the main ideas and content of this passage into a graphic organizer.

Mathematics
1 answer:
otez555 [7]3 years ago
3 0

Answer:

D. A Venn diagram allows you to compare and contrast all different aspects of two types of things and contrast them aswell.

Step-by-step explanation:

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Kiara traveled 190miles in 19hours. Find he speed in miles per hour.
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Answer:

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Step-by-step explanation:

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3 years ago
Simplify -4 • -4 • -4
WARRIOR [948]

Answer: -64

Step-by-step explanation: Since we know that -4 x -4 is a positive, it equals 16, then a positive plus a negative equals a negative, so 16 x -4 equals <u>-64</u>

8 0
3 years ago
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Describe in Words how to find the area of the square given that each side is s inches long
SCORPION-xisa [38]
The area of the square is s^2.
3 0
3 years ago
use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0
2 years ago
PLEASE HELP QUICK 20 PTS!!!<br><br> Which relation is a function?
FinnZ [79.3K]

Answer:

4

Step-by-step explanation:

A function must pass the vertical line test, which means that two coordinates cannot have the same x coordinate. (They can't be directly above each other.)

7 0
4 years ago
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