The total mass of the living things on the farm is 588 kg.
<h2><u>Mass calculation</u></h2>
Since on a farm there was a cow, 2 sheep and 3 chickens, to determine what is the total mass of the 1 cow, the 2 sheep, the 3 chickens, and the 1 farmer on the farm, the following calculation must be performed :
- (6.2 x 10) + (4 x 10 x 10) + (2 x 6 x 10) + (3 x 2 x 1) = X
- 62 + 400 + 120 + 6 = X
- 588 = X
Therefore, the total mass of the living things on the farm is 588 kg.
Learn more about mass calculation in brainly.com/question/14695611
The exponential growth in biology is A=Pert, where "A" is the ending amount of whatever you're dealing with , "P" is the beginning amount of that same "whatever", "r" is the growth or decay rate, and "t" is time. The formula is related to the compound-interest formula, and represents the case of the interest being "compounded continuously".
Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
I believe it’s 250 ounces
