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elena55 [62]
3 years ago
7

Determine the growth defined by the equation y = 6(.79)^x. Is this exponential growth or exponential decay?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer:

exponential decay

Step-by-step explanation:

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Identify the segment bisector of XY.
Ganezh [65]

Given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:

  • Segment bisector of XY = line n
  • Length of XY = 6

<em><u>Recall:</u></em>

  • A line that divides a segment into two equal parts is referred to as segment bisector.

In the diagram attached below, line n divides XY into XM and MY.

Thus, the segment bisector of XY is: line n.

<em><u>Find the value of x:</u></em>

XM = MY (congruent segments)

  • Substitute

5x + 8 = 9x + 12

  • Collect like terms and solve for x

5x + 8 = 9x + 12\\5x - 9x = -8 + 12\\\\-4x = 4\\\\x = -1

XY = XM + MY

XY = 5x + 8 + 9x + 12

  • Plug in the value of x

XY = 5(-1) + 8 + 9(-1) + 12\\\\XY = -5 + 8 -9 + 12\\\\\mathbf{XY = 6}

Therefore, given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:

  • Segment bisector of XY = line n
  • Length of XY = 6

Learn more here:

brainly.com/question/19497953

3 0
2 years ago
How to solve X^4-19x^2+48=0
ZanzabumX [31]
Two numbers that add up to -19 and multiply to 48 are -16 and -3:

(x^4-19x^2+48)=0\\(x^2-16)(x^2-3)=0\\(x+4)(x-4)(x^2-3)=0

So, the solutions come from each parentheses:  x+4=0, x-4=0, and x^2-3=0.

x+4=0
x = -4

x-4=0
x = 4

x^2-3=0
x^2 = 3
x = +/- √3

So, the solutions are -4, -√3, √3, and 4.
4 0
3 years ago
Evaluate.
Jlenok [28]
45 + 2 × [ (45 × 60) + 25]
45 + 2 × 2700 + 25
70 + 5400
5470
5 0
3 years ago
Whats 9 +10 will give brainlest
shtirl [24]

Answer:

19

Step-by-step explanation:

"You stupid"

"No Im not"

"Whats 9+10"

"21"

"You stupid"

4 0
3 years ago
Read 2 more answers
Iona wrote out the description of each step for her multiplication of the binomial and trinomial (2x – 3)(5x2 – 2x + 7)
Olin [163]

Steps for multiplying the given binomial and trinomial (2x-3)\times (5x^{2}-2x+7) are:

Step 1: 2x\times (5x^{2}-2x+7)-3 \times (5x^{2}-2x+7)

Step 2: 10x^{3}-4x^{2}+14x-15x^{2}+6x-21

Step 3: 10x^{3}-19x^{2}+20x-21

7 0
3 years ago
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