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dimulka [17.4K]
3 years ago
11

Match the activities to their respective categories.

Biology
1 answer:
Grace [21]3 years ago
5 0

Answer:

Structural:

- thickness of fur coat;

- type of beak

Behavioural:

- nocturnal nature

- hibernation

- flocking                              

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DNA nucleotides always contain a 5 carbon sugar known as what
Rudik [331]
The 'D' in DNA stands for deoxyribose. 
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3 years ago
Describe the interaction between the farmer, the soil, his corn plants, and the Sun. How does energy flow?
madam [21]

Answer:The farmer uses farm machinery to plot the soil and plant the corn. Energy from the Sun Is stored by the corn plants. When the farmer, animals, or other people eat corn, they gain the energy captured by it.

Explanation:Because it's easy knowledge

8 0
3 years ago
Suppose that xylem were located only in the roots and stems of a plant. Would fluids in the
schepotkina [342]

Answer:

What if xylem were only located in the roots and stems, would fluids still move? No because xylem have stoma that enables transpiration to happen. If you remove xylem, you've removed that "vacuum" that pulls that water upward

Explanation:

4 0
3 years ago
A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 7.8 cm from the axis of rotation. (a) Calcul
Novosadov [1.4K]

Given data:

● Angular velocity of the turntable ω = 33 rev/min

Therefore,

ω = 33 rev/min

ω = 33rev/min × 2π rad/rev × 1 min/60 sec = 3.45 rad/s

● The distance of the watermelon seed from the axis of rotation r = 7.8 cm = 0.078 m

● μs = the coefficient of static friction

Section a:

The seed is undergoes circular motion and it is been effected by centripetal acceleration.

ac = rω^2

ac = 0.078 × 3.45^2

ac = 0.9284 m/s^2

Therefore,

the centripetal acceleration of the seed is 9.274 m/s^2

Section b:

If the seed is observed not to slip at the course of the circular motion, then the supplied frictional force given by the seed and surface of turntable would at least be equivalent to the centripetal force working on the seed.

Centripetal Force = Frictional Force

mrω^2 = μsmg

μs = rω^2 /g

μs = 0.078 × 3.45^2

------------

9.81

μs = 0.09464

Thus,

the coefficient of static friction is 0.09464.

6 0
2 years ago
Plsssssss helppppppppppppp
slega [8]

Answer:

what do you need help with

3 0
3 years ago
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