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valina [46]
3 years ago
8

The average of Aaron's three test scores must be at least

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer:

96

Step-by-step explanation:

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Leviafan [203]

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x = 300 minutes

Step-by-step explanation:

20 + .15x = 35 + .10x

.05x = 15

 

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3 years ago
Im to layz to do my test so ye all the questions worth 10 points
Arisa [49]

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subtract 6 from 27 the divide by 3

Step-by-step explanation:

6 0
3 years ago
The triangular face of the prism shown has an interior angle with a measure of 75º and an exterior angle with a measure of 110°
coldgirl [10]

Answer:

A 35°

Step-by-step explanation:

180°-110°=70°

180°-70°-75°=35°

5 0
3 years ago
What is the measurement of angle W in the shape below? You must include the units.
defon

Answer:

Umm can you not report me please because if I don’t get these points to ask a question I will fail a test :(

Step-by-step explanation:

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3 years ago
To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo
mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}

Given:

\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25

Confidence level = 80%

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0
2 years ago
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