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2 years ago

What is the surface area of this rectangular pyramid?

Mathematics

1 answer:

Elina [12.6K]2 years ago

8 0

Answer:

100 mm i think

Step-by-step explanation:

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2/3 + 1/4 what is a simplified expression?

Anna35 [415]

Answer:

11/12

Step-by-step explanation:

We need to get a common denominator of 12

2/3 *4/4 = 8/12

1/4 *3/3 = 3/12

2/3 +1/4

8/12+3/12

11/12

5 0

2 years ago

What is the area?? Please help

Olegator [25]

Answer:

Step-by-step explanation:

We have the triangle and the rectangle.

The formula of an area of a triangle:

$A_{\triangle}=\dfrac{1}{2}bh$

b - base

h - height

The formula of an area of a rectangle:

$A_{\boxed{\ }}=lw$

l - length

w - width

We have b = 24 ft, h = 7 ft, l = 24 ft and w = 10 ft.

Substitute:

$A_\triangle=\dfrac{1}{2}(24)(7)=(12)(7)=84\ ft^2$

$A_{\boxed{\ }}=(24)(10)=240\ ft^2$

The area of the figure:

$A=A_{\triangle}+A_{\boxed{\ }}$

Substitute:

$A=84+240=324\ ft^2$

7 0

2 years ago

Please answer the following attachment down below.<br><br> I would greatly appreciate it if you did.

zepelin [54]

Answer:

34.63

Step-by-step explanation:

A=a2+2aa2

4+h2=32+2·3·32

4+42≈34.63201

4 0

2 years ago

In the football game between NM and JL. It's the end of the second half and the cougars are attempting a miraculous 50 yard fiel

Yanka [14]

Answer:

88.02 ft/s

Step-by-step explanation:

Angle with the horizontal, θ =25°

Initial velocity, v = 60 mph

1 mph = 1.467 ft/s

60 mph = 60 × 1.467 ft/s = 88.02 ft/s

Vertical component, v sin θ = 88.02 sin 25° = 37.2 ft/s

Horizontal component, v cos θ = 88.02 cos 25°= 79.8 ft/s

3 0

2 years ago

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

3 years ago