4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
D. $3,776.28
Step-by-step explanation:
The finance charge should be ...
$3558.71 × 1.75% = $62.28 . . . . . . not $82.28
The new balance should be $20 less than what is shown, so should be ...
$3,776.28
Answer:
Step-by-step explanation:
1. 1 Simplify 2+6-4d to -4d+8.
7 ( -4d + 8)
therefor, the answer is, 7( -4d + 8)
Answer:
Step-by-step explanation:
Answer:
the first one, and the last one
Step-by-step explanation:
