Answer:
30% probability that it is either red or yellow
Step-by-step explanation:
We have that:
10% of the candies are green
10% of the candies are red
20% of the candies are yellow
20% of the candies are blue
20% of the candies are orange.
The rest is brown. The percentage of brown candies is not important to this problem.
If you pick a candy at random, what is the probability that it is either red or yellow?
10% are red
20% are yellow
10 + 20 = 30%
30% probability that it is either red or yellow
Answer:
nikky ggeibf theke jmbhknfyk be s you know vfub be fj set u in vy d so o ka vgu
4 x 5 x 5 is 100 if u distribute
Now 5 + 5 x 4 is 25
- Cricket = 55%
- Football = 30%
- Other games = Remaining (?)
So, the percent of people who like <u>other games</u> equals:
= 100 – (55 + 30)
= 100 – 85
= 15%
<u>If </u><u>the </u><u>total </u><u>no.</u><u> </u><u>of.</u><u> </u><u>people</u><u> </u><u>is </u><u>6</u><u>0</u><u>,</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u>:
★ Cricket
= 60,00,000 × 55/100
= 33,00,000
★ Football
= 60,00,000 × 30/100
= 18,00,000
★ Other sports
= 60,00,000 × 15/100
= 9,00,000
Answer:
Step-by-step explanation:
We have the statement AB turns clockwise to coincide with BC.
= ABD + DBC
= 33.3° + 30.6°
= 63.9°
Now we have the statement a point E is drawn directly opposite point C. B, E, and C are on the same straight line
EBC is a straight line, so sum of angles =180°
ABE + ABD + DBC = 180°
ABE + 33.3° + 30.6° = 180°
ABE + 63.9° = 180°
ABE = 180 - 63.1
ABE = 116.9° ....
