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tatuchka [14]
3 years ago
11

Gives BRAINLIEST

Mathematics
1 answer:
iren [92.7K]3 years ago
7 0
The answer is X=0 I’m thinking
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Suppose A and B represent two different school populations where A > B and A and B must be greater than 0. Which of the follo
Ulleksa [173]
We can reject the last one: subtracting a non-zero value will result in a smaller value.

So now we have:

<span>2(A + B)
(A + B)2
A2 + B2

If all of them are mulptiplications, then they are all equivalent!

I mean by this, if what you meant is this:

</span>
<span>2*(A + B)
(A + B)*2
A*2 + B*2

If there is no sign, then the multiplication sign is implicit,


and all of these expressions say exactly the same: two of A and two of B.
</span>
6 0
3 years ago
What are the zeros of f(x) = x^2 + x - 20?
kvv77 [185]
X² + x - 20
= (x+5)(x-4)

x + 5 = 0
x = -5

x - 4 = 0
x = 4

hence the answer is C
3 0
3 years ago
Simply the expression 2(6+3n)-4
Ronch [10]

Answer:

8+6n

Step-by-step explanation:

First, distribute the 2 into the parenthesis.

2(6)+2(3n)-4

Then, multiply the numbers.

12+6n-4

Now add(subtract in this case) the common multiples.

12-4= 8

8+6n

Since you can no longer simplify the equation, this is the answer..

8+6n

3 0
3 years ago
A line has slope -3/4 and y intercept 5 which answer is the equation of the line
dolphi86 [110]

Answer:

y= -3/4x +5

Step-by-step explanation:

formula: y=mx+b

m= slope

x= variable

b= y-intercept

plug in the numbers into the formula.

y= -3/4x +5

8 0
3 years ago
Of the 2,598,960 different five-card hands possible from a deck of 52 playing cards, how many would contain all black cards.
kumpel [21]

Answer: 65,780

Step-by-step explanation:

When we select r things from n things , we use combinations and the number of ways to select r things = ^nC_r=\dfrac{n!}{(n-r)!r!}

Given : The total number of playing cards in a deck = 52

The number of different five-card hands possible from a deck = 2,598,960

In a deck , there are 26 black cards and 26 red cards.

The number of ways to select 5 cards from 26 cards = ^{26}C_{5}=\dfrac{26!}{(26-5)!5!}

=\dfrac{26\times25\times24\times23\times22\times21!}{21!(120)}=65780

Hence, the number of different five-card hands possible from a deck of 52 playing cards such that all are black cards = 65,780

3 0
3 years ago
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