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3 years ago

Can somebody please help me out for brainliest

Mathematics

1 answer:

Troyanec [42]3 years ago

8 0

Answer:

yo do people actually answer these? anyways amos: arianasurf.2020

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Can someone please help me solve and simplify this??

Viefleur [7K]

Answer:

The Answer is -x + 3.

Step-by-step explanation:

It's honestly one of the longest process'. Above is the right answer though. Hope it helped.

7 0

3 years ago

What is 4/16 ÷ 3/4

Kobotan [32]

Answer:

4/12 simplified to 1/3.

Step-by-step explanation:

4/16 x 4/3 = 4/12

4/12 = 1/3

5 0

3 years ago

Read 2 more answers

Nik and his friend bought shares of stock at the rate of $32 per share. For $3,520, Nik's friend bought 10 fewer shares than Nik

Svetradugi [14.3K]

Answer:

#1-List all outcomes for choosing the digit. *

A: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

B: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

C: 1, 2, 3, 4, 5, 6, 7, 8, 9

OD: a number

Both B and C

Step-by-step explanation:

7 0

3 years ago

6x^8 + 4x^5 + (n + 1)x^2-n / 10x - 10<br> quien me ayuda

Neporo4naja [7]

Answer:

parte 1) | Superprof

1 Indica cuáles de las siguientes expresiones son monomios. En caso de ... 4 Encuentra el valor numérico del polinomio P(x) = x^3 + 3x^2 - 4x - 12 ... d) (10x – 5/4x³ + 5/2x² – 1/2) : (5x)

7 0

3 years ago

a study timed left-handed and right-handed people to see how long it took them to hit a buzzer. the data is shown below: the six

Effectus [21]

The z or t score to be used is (0.422,0.978)

How to find the critical value ?

Critical probability (p*) = 1 - (Alpha / 2), where Alpha is equal to 1 - (the confidence level / 100), is the unit statisticians use to determine the margin of error within a set of data in statistics.

The critical value for α = 0.13 is $z_{c} = \frac{z_{1} - \alpha }{2}$

The corresponding confidence interval is computed as shown below

$CI = (X1_{1} - X_{2}- z_{c} \sqrt{\frac{a_{1}^{2}}{n_{1} } + \frac{a_{2}^{2}}{n_{2} }} , X1_{1} - X_{2}+z_{c} \sqrt{\frac{a_{1}^{2}}{n_{1} } + \frac{a_{2}^{2}}{n_{2} }} )$

$CI = (2.1 - 1.4- 1.514\sqrt{\frac{1^{2}}{37 } + \frac{0.5_{2}^{2}}{38 }} , 2.1 - 1.4 + 1.514 \sqrt{\frac{1^{2}}{37 } + \frac{0.5^{2}}{38 }} )$

CI = (0.422, 0.978)

0.422< mu1 - mu 2 < 0.978

To learn more about finding the critical value from the given link

brainly.com/question/14040224

#SPJ4

8 0

1 year ago