Find the value of y.
2 answers:
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Answer:
Race completed in 48 minutes.
Step-by-step explanation:
Let the speed of Max on hoverboard is = x
Then as per question speed of Victoria on hoverboard = 3x
Now it has been given in the question that speed of Victoria on foot is 1/3 of the speed of Max on hoverboard that will be = x/3
Now we will form the equation.
As we know the formula speed = distance/time
Let the time taken by both to complete the race be t minutes.
Distance covered by Victoria in 12 minutes + Distance covered by Victoria on foot = distance covered by Max on hoverboard
Then the equation will be
12(3x)+(1/3)x(t-12)=xt
So 48 minutes it took to complete the race.
Re-write with a common denominator, in this case 12:
Add:
Answer:
see attached
Step-by-step explanation:
Dilation is the transformation that changes the size of something. When you choose ×110% on a copy machine, you are making all the dimensions in the copy equal to 1.1 times the dimensions of the original, for example. That is dilation by a factor of 1.1, or 110%.
Here, you're asked to dilate triangle ABC by a factor of 3. That means all of the dimensions on the dilated figure will be 3 times their length on the original.
The center of dilation is point P. That means all the distances from point P are multiplied by 3.
In the attached figure, a gray arrow has been drawn from point P to each of the points A, B, and C. Then two more arrows of the same length are drawn in the same direction. The total distance at the end of the 3 arrows is 3 times the original distance from point P. These are the points A', B', and C' you are asked to draw. Connecting these points gives the dilated triangle A'B'C'.
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You could think of point P (the center of dilation) as having coordinates (0, 0). Then points A, B, and C would have coordinates A(-4, 0), B(0, -3), and C(-4, -3). To dilate these points by a factor of 3, multiply each coordinate value by 3: A'(-12, 0), B'(0, -9), C'(-12, -9). You will see that these are the coordinates of the vertices of the dilated triangle.
