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3 years ago

Find the distance between the points (-7, -10) and (-5, -1)

1 answer:

7 0

Find the Distance Between Two Points
Use the distance formula to determine the distance between two points.
Exact Form:
√85

Decimal Form:
9.21954445
…

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I am having a hard time with this page if someone can help me i will appreciate it a lot!!

Allisa [31]

Answer:

#1 is It could be another girl or it could be a boy

#2 is Its could be another boy or it could be a girl.

The diagram should look like this:

BB. BG

GB GG

#4 is 4

#5 is 1

#6 is there is 1/2 a change the baby can be a girl and a 1/2 change the baby can be a boy. For both of them to be girls; it would be 1/4 chance.

5 0

3 years ago

2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.

likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4 + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

$y = ^+_- \sqrt{-x^2+4x+4} -5$

Thus

$f(x) = \sqrt{-x^2+4x+4} - 5$

$g(x) = -\sqrt{-x^2+4x+4} - 5$

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

$\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0$

The quadratic has roots

$\frac{52 ^+_-\sqrt{1664}}{26}$

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

5 0

3 years ago

If f(g(x)) = (x-3)^4 what is f(x) and g(x)

Lelechka [254]

One possible solution is

f(x) = x^4

g(x) = x-3

Since

f(x) = x^4

f(g(x)) = ( g(x) )^4

f(g(x)) = ( x-3 )^4

=================================================

Another possible solution could be

f(x) = x^2

g(x) = (x-3)^2

Because

f(x) = x^2

f(g(x)) = ( g(x) )^2

f(g(x)) = ( (x-3)^2 )^2

f(g(x)) = (x-3)^(2*2)

f(g(x)) = (x-3)^4

6 0

3 years ago

56 POINTS! Find the area of the following figure. Explain how you got your answer.

AleksAgata [21]

Answer:

26.5 units²

Step-by-step explanation:

I am splitting the figure into a rectangle and two triangles to make this easier for me.

The rectangle is b•h so 5•4 = 20 units²

Area of triangle=1/2bh

The left triangle is $\frac{1}{2}$ (3•3) ---> $\frac{1}{2}$ (9) ---> 4.5 units²

The right triangle is $\frac{1}{2}$ (2•2) ---> $\frac{1}{2}$ (4) ---> 2 units²

Then add it all up: 20+4.5+2 = 26.5 units²

3 0

2 years ago

HELP ASAP. solve for x

svp [43]

Answer:

x = 80

Step-by-step explanation:

x + 30 = 110 (Opposite angles are equal)

x = 110 - 30

x = 80

4 0

3 years ago