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Daniel [21]
2 years ago
15

Describe the relationship between the value of (126+9) and (126+9) / 2.

Mathematics
2 answers:
BaLLatris [955]2 years ago
6 0
The relationship between (126+9) is that you are just adding and for (126+9)/2 you are still adding but after you find your answer you then divide by 2
Burka [1]2 years ago
5 0
Hello!, 

First we now they both equal 135 

There both in () 

there both addition 
 
I hope it helped! 
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Answer:

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Step-by-step explanation:

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Does anyone know how to solve this?
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Given :

A right angle triangle ABC .

To Find :

The perimeter of ABC .

Solution :

Since, triangle ABC is right angled and angle ∠ABC is 46° .

So, AC = AB cos 46° = 7.64 units.

Also, CB = AB sin 46° = 7.91 units.

Therefore, the perimeter of ΔABC is :

P = 11 + 7.64 + 7.91 units

P = 26.55 units

Hence, this is the required solution.

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What triangle is 8, 11, 12. right, acute, obtuse, none
krek1111 [17]

Answer:

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Step-by-step explanation:

7 0
2 years ago
6. (4.2.12) Of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired. a. F
nata0808 [166]

Answer:

(a) Probability that a randomly chosen item is defective and cannot be repaired is 8%.

(b) Probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is 0.2711.

Step-by-step explanation:

We are given that of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired.

Let Probability that item are defective = P(D) = 0.20

Also, R = event of item being repaired

Probability of items being repaired from the given defective items = P(R/D) = 0.60

<em>So, Probability of items not being repaired from the given defective items = P(R'/D) = 1 - P(R/D) = 1 - 0.60 = 0.40 </em>

(a) Probability that a randomly chosen item is defective and cannot be repaired = Probability of items being defective \times Probability of items not being repaired from the given defective items

              = 0.20 \times 0.40 = 0.08 or 8%

So, probability that a randomly chosen item is defective and cannot be repaired is 8%.

(b) Now we have to find the probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 20 items

            r = number of success = exactly 2

           p = probability of success which in our question is % of randomly

                  chosen item to be defective and cannot be repaired, i.e; 8%

<em>LET X = Number of items that are defective and cannot be repaired</em>

So, it means X ~ Binom(n=20, p=0.08)

Now, Probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is given by = P(X = 2)

   P(X = 2) = \binom{20}{2} \times 0.08^{2} \times  (1-0.08)^{20-2}

                 = 190 \times 0.08^{2}  \times 0.92^{18}

                 = 0.2711

<em>Therefore, probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is </em><em>0.2711.</em>

             

6 0
3 years ago
How do you write 60,000 in exponential notation
andrey2020 [161]
6x10^4
That is the answer
7 0
2 years ago
Read 2 more answers
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