Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
Maybe 74
Step-by-step explanation:
42+64=106
180-106=74
Answer:
The only possible answer that is correct is the first one, x = -4.
Step-by-step explanation:
Simplify the given inequality as much as possible, and then substitute each of the given x values one by one to determine which is in the solution set.
9(2x + 1) < 9x - 18 becomes 18x + 9 < 9x - 18, which, if reduced by dividing all four terms by 9, becomes 2x + 1 < x - 2.
Simplifying further, we get x < - 3. The only possible answer that is correct is the first one, x = -4. -4 < -3 is true.
Answer:
22.046 lbs
Step-by-step explanation:
10kg is rounded to 22 pounds
Answer:
Below
Step-by-step explanation:
9 
