Explanation:
For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.
For example, 
, 
and 
all these compounds contain an electronegative atom attached to hydrogen atom.
Therefore, these pure compounds will exhibit hydrogen bonding.
Thus, we can conclude that out of the given options , and are the pure compounds which will exhibit hydrogen bonding.
The correct answer is D
Explanation:
Wave frequency is mainly determined by the number of waves that pass through a specific point. In a diagram, this can be found by analyzing the number of crests (top of the wave) and the space between them. For example, wave B is the one with the lowest frequency because there is only one crest and this shows only one wave passing at a specific point. On the opposite, wave D is the one with the highest frequency because this shows multiple crests and this indicates the frequency is high or that many waves pass through a specific point in a short time.
A) Mass Number
B) Protons and Electrons
C) (I think group but I'm not 100% sure on this...)
D) 12 (To work out the number of neutrons you do MASS number - ATOMIC number aka the number of protons so in this case you'd do 23-11=12)
Hope this helps
One mole of copper equals 6.02 × 10^23 atoms. The answer is letter C. This follows the
Avogaro’s law wherein 1 mole of a substance is equal to 6.02 x 10^23 atoms,
formula units or molecules. This is applicable to all substances.
