Nance I need help hihihihihihihi
1 answer:
You might be interested in
Now the first mechanic takes 4 days to do the job, so after he has worked for 1 day only, he has done 1/4 of the whole thing.
the second mechanic can do it in 6 days, so after 1 day only of work, he has done 1/6 of the whole thing.
the third mechanic can do it in 8 days, so after a day, he has done 1/8 of the total work.
now, if they all three work together, after 1 hour has gone by, the first mechanic has done 1/4 of the whole thing, the second mechanic has done 1/6 of it, and the last one, has done 1/8.
let's say it took all three working together "t" days, that means after 1 hour of work, they all combined have done 1/t of the whole thing, thus
the second mechanic can do it in 6 days, so after 1 day only of work, he has done 1/6 of the whole thing.
the third mechanic can do it in 8 days, so after a day, he has done 1/8 of the total work.
now, if they all three work together, after 1 hour has gone by, the first mechanic has done 1/4 of the whole thing, the second mechanic has done 1/6 of it, and the last one, has done 1/8.
let's say it took all three working together "t" days, that means after 1 hour of work, they all combined have done 1/t of the whole thing, thus
solve for "t"