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timurjin [86]
3 years ago
9

(-6)(-7)= _____ what" please ASAP"

Mathematics
2 answers:
wariber [46]3 years ago
7 0

Answer:

42

Step-by-step explanation:

-6x-7 = 6x7 = 42

lara31 [8.8K]3 years ago
4 0

Answer:

(-6)(-7) = 6 x 7 = 42

Hope this helps!

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which polynomial represents the sum below? (3x^2+3) + (3x^2+x+4) A) 6x^2+x+12 B) 9x^2+x+7 C) 6x^@+x+7 d)9x^2+x+12
mezya [45]

Answer:

Step-by-step explanation:

3x^2 + 3 + 3x^2 + x + 4....combine like terms

6x^2 + x + 7 <===

4 0
3 years ago
Someone please help me with number 8!! urgent
Papessa [141]

Answer:

y mean yellow

Step-by-step explanation:

y mean yellow. the answer for numbber 8

8 0
2 years ago
a musician's hair was originally 3 inches long she asked the hairdresser to cut 5/6 of it off how many inches did she have cut o
True [87]
It would be half an inch long because there is 6 halves in 3 so 5/6 of it would be half an inch
5 0
3 years ago
Carolyn and Joyce ordered a large pizza that had 12 slices. Carolyn ate 1
kondor19780726 [428]

Answer:

They ate \frac{1}{3} of the pizza

Step-by-step explanation:

Carolyn and Joyce at 4 slices of pizza altogether, and since there are 12 slices of pizza, they ate \frac{4}{12}=\frac{1}{3} of the pizza.

5 0
2 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
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