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Lorico [155]
3 years ago
7

HURRY! One of the roots of the equation

x^{2} -12x+c=0" alt="5x^{2} -12x+c=0" align="absmiddle" class="latex-formula"> is 5 times as big as the other root. Find the value of c.
NOT C=5.4
Mathematics
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

<em>c = 4</em>

Step-by-step explanation:

x + 5x = 12/5

30x = 12

x_{1} = 2/5

x_{2} = 2

<em>c </em>= [(2/5)*2] * 5 =<em> 4</em>

(5x - 2)(x - 2) = 0

5x² - 12x + 4 = 0

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Which statement is true
loris [4]

Answer:


Step-by-step explanation


You must find the common denominator for all of them.  


A is correct. 13 x 2 is 26 and 14 x 2 is 28. Therefore, 13/14 is greater than 25/28.


B is not correct. 4 x 5 is 20 and 9 x 5 is 45. 4/9 is actually less than 21/45.


C is not correct. 5 x 2 is 10 and 6 x 2 is 12. 5/6 is actually less than 11/12.


D is not correct. 4 x 5 is 20 and 5 x 5 is 25. 4/5 is actually less than 8/25.

4 0
3 years ago
Hey yall i would really appreciate your help on this plz
Katarina [22]

Answer:

the length of the opposite side (x), is 27.2

Step-by-step explanation:

For the given right triangle problem;

the opposite side of the given angle, opp. = 22

the hypothenuse side,  hypo. = x

given angle of the triangle, θ = 54⁰

The length of the opposite side (x), is calculated as follows;

sin \ \theta = \frac{opp.}{hypo.} \\\\sin (54) = \frac{22}{x} \\\\x = \frac{22}{sin(54)} \\\\x = 27.2

Therefore, the length of the opposite side (x), is 27.2

6 0
3 years ago
The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
ankoles [38]

Answer:

     2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

  T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

  D_x=T_x\sqrt{T_x}

The mean distance of planet Y can be found using the given relation ...

  T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x

The mean distance of planet Y is increased from that of planet X by the factor ...

  2√2

8 0
2 years ago
Find the place value of 8 in 2456.1387.<br> Tenths<br> Hundredths<br> Thousandths<br> Thousands
rjkz [21]

Answer: Third Choice. Thousandths

Step-by-step explanation:

<u>Concept:</u>

Here, we need to know the order and name of each place value.

Please refer to the attachment below for the specified names.

<u>Solve:</u>

<em>STEP ONE: Orde and name each place</em>

2 ⇒ One Thousands

4 ⇒ Hundreds

5 ⇒ Tens

6 ⇒ Ones

.

1 ⇒ Tenths

3 ⇒ Hundredths

8 ⇒ One Thousandths

7 ⇒ Ten Thousandths

<em>STEP TWO: Find the number [8] in the number</em>

As we can see from the list above, 8 is at the right of the decimal point, thus, the place value is <u>Thousandths</u>.

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
The length between (3, 8) and (-2, -4) is ______?
True [87]

Answer:

13

Step-by-step explanation:

to find the length between two point you've got to use the formula

√(x2-x1)^2 +(y2-y1)^2

√(-2-3)^2 + (-4-8)^2

√(-5)^2 + (-12)^2

√ 25+144

√169

13

5 0
3 years ago
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