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3 years ago

7

HURRY! One of the roots of the equation

x^{2} -12x+c=0" alt="5x^{2} -12x+c=0" align="absmiddle" class="latex-formula"> is 5 times as big as the other root. Find the value of c.
NOT C=5.4

1 answer:

kotegsom [21]3 years ago

5 0

Answer:

<em>c = 4</em>

Step-by-step explanation:

x + 5x = 12/5

30x = 12

$x_{1}$ = 2/5

$x_{2}$ = 2

<em>c </em>= [(2/5)*2] * 5 =<em> 4</em>

(5x - 2)(x - 2) = 0

5x² - 12x + 4 = 0

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