HURRY! One of the roots of the equation
x^{2} -12x+c=0" alt="5x^{2} -12x+c=0" align="absmiddle" class="latex-formula"> is 5 times as big as the other root. Find the value of c.
NOT C=5.4
1 answer:
Answer:
<em>c = 4</em>
Step-by-step explanation:
x + 5x = 12/5
30x = 12
= 2/5
= 2
<em>c </em>= [(2/5)*2] * 5 =<em> 4</em>
(5x - 2)(x - 2) = 0
5x² - 12x + 4 = 0
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