Answer:
a = 2, r = 5
Step-by-step explanation:
Nth term of a GP = a×r^(n-1)
Where 'a' is the first term and 'r' is the common ratio
4th term = a×r^3 = 250
r^3 = 250/a
7th term = a×r^6 = 31250
a×r^6 = 31250
a×(r^3)^2 = 31250
a×(250/a)^2 = 31250
a×(62500/a^2) = 31250
62500/a = 31250
a = 62500/31250 = 2
a = 2
since r^3 = 250/a,
r^3 = 250/2 = 125
r = (125)^(1/3)
r = 5
Answer:
x = 7/2 = 3.500
x = 4
x= 0.0000 - 1.4142 i
x= 0.0000 + 1.4142 i
Step-by-step explanation:
sorry if its wrong
Answer:
1927 times
Step-by-step explanation:
To do this, you divide the second value by the first value.
This gives us 188,869 divided by 98, which equals around 1927.
Hope this helps.
f(0) = -3(0) + 5 = 5
f(-4) = -3(-4) + 5 = 17
f(6) = ½(6) - 4 = -1
f(9) = 2
f(2) = ½(2) - 4 = -3
Using the restraints, find which equation the f(x) function validates and plug it in.
Answer:
probability for 3 on a dice (P3) in one dice =
probability for even no. of a dice (Pe) =
Therefore, the probability of finding 3 on one dice and even on another (P) = P3 + Pe
