Answer:
Step-by-step explanation:
In the past, mean of age of employees
i.e. 
Recently sample was taken
n = sample size = 60
Mean of sample = 45
Std dev of sample s = 16

(Right tailed test)
Since only population std deviation is known we can use t test only
Std error = 
Mean difference = 45-40 =5
Test statistic t=
df = 60
p value =0.008739
Since p < 0.05 we reject null hypothesis
The mean age has increased.
Answer:
-20
Step-by-step explanation:
(r + b − g)(b + g)
we have fom statement:
r = 9
b = 5
g= −6
so we have:
(r + b − g)(b + g)= (9+5-(-6))*(5+(-6))
(r + b − g)(b + g)= (14+6)*(-1)
(r + b − g)(b + g)= -20
Answer:
If the population grows by 4% each year then
the population in any given year is 104% of
the previous year or 1.04 times as much
P(t) = P0(1.04)t
P(t) is population at time t years
P0 = initial population = 11,000
t = number of years = 15
P(15) = 11,000(1.04)15
P(15) = 19,810 people
Step-by-step explanation:
Answer:
(x, y) ⇒ (x -7, y)
Step-by-step explanation:
The y-coordinates are unchanged. Each x-coordinate of the image is 7 units less than the corresponding pre-image coordinate. As a rule, this is ...
(x, y) ⇒ (x -7, y)
One of the ways to find the answer is to find how much 1 percent of 150 is. To do that we just have to divide 150 by 100:
150 / 100 = 1.5
Now we can divide 9 by 1.5 to know how much percent of 150 it is:
9 / 1.5 = 6
Let's check it:
150 * 6% = 150 * 6/100 = 15 * 6/10 = 3 * 6/2 = 18/2 = 9
It's correct then :)