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Nikitich [7]
3 years ago
11

Find an equation of the line passing through the given points. Write the equation in the function notation.

Mathematics
2 answers:
zalisa [80]3 years ago
7 0
<h2>straight line equation</h2>

known two points namely (3,4) and (4,1)

<em><u>the formula looking for equations if known two points is </u></em>

<em><u>\frac{x2 - x1}{x1 - x}  =  \frac{y2 - y1}{y1 - y}</u></em>

<em><u>You can enter the numbers provided above into the </u></em><em><u>formula</u></em>

\frac{x2 - x1}{x1 - x}  =  \frac{y2 - y1}{y1 - y}  \\  \frac{4 - 3}{3 - x}  =  \frac{1 - 4}{4 - y}  \\  \frac{1}{3 - x}  =  \frac{ - 3}{4 - y}  \\  - 9 + 3x = 4 - y \\ y =  - 3x + 13

<em><u>You can check the function is true or </u></em><em><u>false</u></em>

(3,4) 3=x and 4=y

y = -3(3) + 13

y = -9 + 13

y = 4 ✔️

*additional :

y = -3x + 19 ===== f(x) = -3x + 19

Mrrafil [7]3 years ago
3 0
First you need to find the slope of the line using the given coordinates of the two points.
The slope of the line = (1-4)/(4-3) = -3
Then you choose one pair of the coordinates given, either (3,4) or (4,1) , up to you, to find the equation of the line.
If you choose (3,4)
Then
(y-4)/(x-3) = -3
(y-4) = -3x+9
y = -3x+13

If you choose (4,1),
Then
(y-1)/(x-4) = -3
y-1 = -3x+12
y = -3x+13

So, F(x)=-3x+13
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a= one side= 68 mi
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68^2 + 80^2= c^2
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ANSWER: The distance from Greenville to Columbia is 104.995 miles (rounded to 105 miles).

Hope this helps! :)
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