Answer:
Probability that this whole shipment will be accepted is 0.7324.
Step-by-step explanation:
We are given that a company purchases shipments of machine components and uses this acceptance sampling plan: Randomly select and test 30 components and accept the whole batch if there are fewer than 3 defectives.
The above situation can be represented through Binomial distribution;

where, n = number of trials (samples) taken = 30 components
r = number of success = fewer than 3
p = probability of success which in our question is % rate
of defects, i.e; 6%
<em>LET X = Number of defective components</em>
So, it means X ~ 
Now, Probability that this whole shipment will be accepted only when there are fewer than 3 defectives = P(X < 3)
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)
=
=
= 0.7324
Therefore, probability that this whole shipment will be accepted is 0.7324.
Answer:
$5.85
Step-by-step explanation:
To find the percentage of things you can use the percentage formula
p%*x=y
45%*12.99=y
.45*12.99=y
y=5.8455
I rounded up but the question may call for something different. Hope this Helps!
3( m - 3) + 4 = 3m - 9 + 4 = 3m - 5
Answer:
Step-by-step explanation:
The book shelf arrived at the wholesale price = $ 147
Mark up on the furniture = 60 %
So The Cost Price = $147
Markup = 60% = 0.60
So using the formula
Sale Price = Cost Price + Cost Price * Markup percentage
So
Sale Price = 147 + 147*(0.60)
Sale Price = $ 235.20