Answer:
what is expected at 7am is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.
Step-by-step explanation:
In this question, we are asked to calculate if the prediction made by an equation modeled is correct.
Firstly let’s look at the equation in question;
y = 3t - 6
where y is the snow depth and t is the number of hours after midnight.
now we are looking at 7am, that’s 7 hours past 12am, meaning 7 hours after midnight.
let’s plug the value of t as 7 into the equation
y = 3(7) - 6
y = 21-6
y = 15 inches
according to the equation by Kevin, what is expected is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.
Answer:
a) Bar chart
b) Histogram
c) Bar chart
d) Histogram
Step-by-step explanation:
a) Trash pick-up DAY for each HOUSEHOLD in Ames - This is categorical data because, we are talking about days of the week. For instance, Household 1 might have Sunday as Trash pick-up day and that could be accumulated into frequency. Hence, BAR chart is the most appropriate.
b) Patient WAIT-TIME at ISU. This is continuous (quantitative) data. And the most appropriate is HISTOGRAM.
c) Number of trips taken during a GIVEN SCHOOL YEAR by EACH ISU STUDENT. Let say we have 5 ISU STUDENTS. Student 1 had 5 trips, student 2 had 10 trips, etc.
We want to see which student has the most and least trip in that particular school year. Although is count data but the most appropriate graphical display is BAR chart.
d) TAX BRACKET of ALL Iowa RESIDENTS. This is a continuous (quantitative) data. The most appropriate graphical display is HISTOGRAM.
Answer:
∠AOB = 120°
∠BOC = 140°
∠BOD = 140°
Step-by-step explanation:
First, find X !
Full circle is 360°
360 = (2x + 80) + (5x + 40) + 4x + x
360 = 12x + 120
240 = 12x
x = 20°
Substitute the X
∠AOB ≡ (2x + 80) =
(2(20) + 80) = 120°
∠BOC ≡ (5x + 40) =
(5(20) + 40) = 140°
∠BOD = ∠AOB + ∠DOA ≡
120 + x = 120 + 20 = 140°
No of out comes =216
favorable outcome=3
<span>probability that 5 will not appear on the die=3/216</span>
