All categories

3 years ago

How many moles of "02" are in a 192g sample of O2? * 1 2 3 4 5 6 7

Chemistry

1 answer:

Zarrin [17]3 years ago

8 0

Answer: The number of moles of $O_2$ are 6.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

Given mass = 192 g

Molar mass = 32 g/mol

$\text{Number of moles}=\frac{192g}{32g/mol}=6mol$

The number of moles of $O_2$ are 6.

You might be interested in

BRAINLIEST IF RIGHT

vampirchik [111]

A or c probably I think a tho

6 0

3 years ago

Which statement describes a reason to consider air a mixture? A) The major constituents of air are gaseous elements. B) The comp

umka21 [38]

The correct answer is - A) The major constituents of air are gaseous elements.

With the statement ''the major constituents of air are gaseous elements'' we can easily conclude that the air is a mixture. The reason for that is that we have a plural usage of the word element, elements, which mean that there are multiple elements that make up the air.

The air is indeed predominantly a mixture of gaseous elements. The most abundant gas in the air being the nitrogen with 78.9%, oxygen with 20.95%, argon 0.93%, and carbon dioxide 0.04%, with lesser amounts of other gases also be present in it. The water vapor is also present in the air, though it is variable, being around 1% at sea level, but only 0.4% over the entire atmosphere.

3 0

4 years ago

A ball is thrown straight up into the air with a speed of 21 m/s. If the ball has a mass of 0.1 kg, how high does the ball go? A

Grace [21]

Answer:

answer = 22.5m

Explanation:

using

$s = \frac{ {v}^{2} - {4}^{2} }{2a}$

s= (0²-21²)/2(-9.8)

s= -441/19.6

s= 22.5m

do consider marking as Brainliest if this helped!!

5 0

3 years ago

List all possible oxidation numbers for the elements. 21. Al

Alex73 [517]

Answer:

21. Al (Aluminium)

+3 (most common), -1, -2, +1, +2

22. Bi (Bismuth)

+3 (most common), -3, -2, -1, +1, +2, +4, +5

23. Ni (Nickel)

+2 (most common), -2, -1, 0,+1, +3, +4

24. Xe (Xenon)

0 (most common), +1, +2, +4, +6, +8

25. Pb (Lead)

+2 (most common), +4 (most common), -4, -2, -1, +1, +3

Explanation:

Now we proceed to present the answers for each element:

21. Al (Aluminium)

+3 (most common), -1, -2, +1, +2

22. Bi (Bismuth)

+3 (most common), -3, -2, -1, +1, +2, +4, +5

23. Ni (Nickel)

+2 (most common), -2, -1, 0,+1, +3, +4

24. Xe (Xenon)

0 (most common), +1, +2, +4, +6, +8

25. Pb (Lead)

+2 (most common), +4 (most common), -4, -2, -1, +1, +3

7 0

3 years ago

Calculate the number of moles of Li3PO4 in 2.2 L of a 0.60 M Li3PO4 solution.

Bingel [31]

Answer:

1.32 mole

Explanation:

The following data were obtained from the question:

Volume of solution = 2.2L

Molarity of solution = 0.60M

Mole of Li3PO4 =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:

Molarity = mole /Volume

With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:

Molarity =mole /Volume

0.6 = mole of Li3PO4 /2.2

Cross multiply

Mole of Li3PO4 = 0.6 x 2.2

Mole of Li3PO4 = 1.32 mole

Therefore, 1.32 mole of Li3PO4 is contained in the solution.

4 0

3 years ago