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max2010maxim [7]
4 years ago
12

Which statement describes a reason to consider air a mixture? A) The major constituents of air are gaseous elements. B) The comp

onents of air can be separated by chemical processes. C) The original chemical properties of all the components remain intact. D) The major constituent is nitrogen, which does not react with other components.
Chemistry
1 answer:
umka21 [38]4 years ago
3 0

The correct answer is - A) The major constituents of air are gaseous elements.

With the statement ''the major constituents of air are gaseous elements'' we can easily conclude that the air is a mixture. The reason for that is that we have a plural usage of the word element, elements, which mean that there are multiple elements that make up the air.

The air is indeed predominantly a mixture of gaseous elements. The most abundant gas in the air being the nitrogen with 78.9%, oxygen with 20.95%, argon 0.93%, and carbon dioxide 0.04%, with lesser amounts of other gases also be present in it. The water vapor is also present in the air, though it is variable, being around 1% at sea level, but only 0.4% over the entire atmosphere.

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Select all the correct images.<br> Select the atomic models that belong to the same element.
Alex_Xolod [135]

Answer:The 2nd and 3rd one.

Explanation:

It has the same number of protons but different amount of nuetrons.

7 0
3 years ago
Please help me ASAP
blondinia [14]

Answer:

weak acid

Explanation:

pH scale is from 0 to 14

pH =7 is for water which is neutral.  it is neither acidic or basic as the hydrogen ion concentration is equal to hydroxyl ion concentration.

Lesser the pH value than 7 greater the acidic nature. And greater the pH value  than 7 more the basic nature.

Given pH=3-7 So the indicated interval represents weakly acidic.

4 0
3 years ago
The electronic configuration of an element is given below.
Shalnov [3]

Answer:

It is reactive because it has to gain an electron to have a full outermost energy level.

Explanation:

The electron configuration of oxygen is 1s2,2s2 2p4.

Oxygen is in group six in the periodic table so it has six electrons in its valence shell. This means that it needs to gain two electrons to obey the octet rule and have a full outer shell of electrons (eight).  

3 0
2 years ago
An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined
e-lub [12.9K]

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

7 0
3 years ago
The density of a 45.0 mass % solution of ethanol (C2H5OH) in water is 0.873 g/mL. What is the molarity of the solution?
antoniya [11.8K]

Answer : The concentration of solution is, 8.53 M.

Explanation :

As we are given, 45.0 mass % solution of ethanol in water that means 45.0 g of ethanol present in 100 g of solution.

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}

\text{Volume of solution}=\frac{100g}{0.873g/mL}=114.5mL

Now we have to calculate the molarity of solution.

Mass of C_2H_5OH = 45.0 g

Volume of solution = 114.5 mL

Molar mass of C_2H_5OH = 46.07 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }C_2H_5OH\times 1000}{\text{Molar mass of }C_2H_5OH\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{45.0g\times 1000}{46.07g/mole\times 114.5mL}=8.53mole/L=8.53M

Therefore, the concentration of solution is, 8.53 M.

6 0
3 years ago
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