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2 years ago

Is BC a line segment, a ray, or a line

Mathematics

2 answers:

Anettt [7]2 years ago

7 0

Answer:

Line Segment

Step-by-step explanation:

A line segment has dots on both ends of the line. A line has nothing at either end of it. A ray has an arrow at one end of the line. Line BC is a line segment.

Hope it helps!

natta225 [31]2 years ago

7 0

<h3>Answer: BC is a line segment</h3>

Explanation:

This is because we have two fixed endpoints, B and C, where the line does not go on forever beyond those endpoints. This means BC is some fixed length. The terms "line segment" and "segment" are the same thing.

A ray on the other hand would have the line go on forever in one direction, while it only has one fixed endpoint. As the name suggests, think of the ray of sunlight as an example. So we can rule out "ray". We can also rule out "line" because it doesn't extend forever in both directions.

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Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)

mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)

27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

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2 years ago

Geometry please help asap!

m_a_m_a [10]

Step-by-step explanation:

AB = 3

by similaritiy criterion

CE/ CB= ED/AB

4/6= 2/AB

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3 years ago

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Digiron [165]

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3 years ago

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Alex

$Use\ (a\cdot b)^n=a^nb^n\\-----------------\\\\(4ab)^2=4^2a^2b^2=\huge\boxed{16a^2b^2}$

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3 years ago

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koban [17]

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2 years ago