Answerrr? Please I need help
2 answers:
Answer:
21
Step-by-step explanation:
+ 11g - 4h
f = 3, g = 2 and h = 7.
Substitute the above values into the expression.
+ 11 × 2 - 4 × 7
Since there's no addition, subtraction or division signs between 11g and 4h, this basically shows that it is multiplied. Simplify further...
is 3×3×3 which equals to 27
11 × 2 equals to 22, and
-4 × 7 = -28
Put all these found values into an expression.
27 + 22 - 28
Use the B.O.D.M.A.S. rule. First we have to add then subtract.
(27 + 22) - 28
49 - 28 = 21
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Answer:
A. 1
B. .
Step-by-step explanation:
We have been given an equation of a line .
A. We know that slope of parallel lines is always equal,
We can see that slope of our given line is 1, therefore the slope of the line parallel to our given line would be 1.
B. We know that the product of slopes of two perpendicular lines is .
Let m represent slope of perpendicular to our given line, then:
Therefore the slope of the line perpendicular to our given line would be .
Answer:
y(s) =
we will compare the denominator to the form
comparing coefficients of terms in s
1
s: -2a = -10
a = -2/-10
a = 1/5
constant:
hence the first answers are:
a = 1/5 = 0.2
β = 5.09
Given that y(s) =
we insert the values of a and β
=
to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A
5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)
-52 = B(26)
B = -52/26 = -2
to get A lets substitute s=0.4
5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)
-51 = 0.2A - 52.08
0.2A = -51 + 52.08
A = -1.08/0.2 = 5.4
<em>the constants are</em>
<em>a = 0.2</em>
<em>β = 5.09</em>
<em>A = 5.4</em>
<em>B = -2</em>
<em></em>
Step-by-step explanation:
- since the denominator has a complex root we compare with the standard form
- Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
- substitute the values gotten into the function
- Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
- after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above
Thanks...