find the equation of a line that goes through the point (2,-3) and is perpendicular to the line y= -2/5x+6
2 answers:
Find the negative reciprocal of the given line's slope in order to determine what the slope of the line will be. -2/5 -> -5/2 -> 5/2 Your line now looks like this: y = 5/2x + b Now, substitute the given point into the y and x variables and solve for b. y = 5/2x + b -3 = 5/2(2) + b -3 = 5 + b -8 = b You are now done. The line is y = 5/2x - 8.
To get a perpendicular line to y=-2/5x+6 all you need to do is get the negative reciprocal of the slope then use (2,-3) and point slope formula to get your new equation. y=-2/5x+6 m=-2/5 so new equation slope is m=5/2 y−b=m(x−a<span>) or y-y1=m(x-x1)</span> point is (2,-3) plug and chug y-(-3)=5/2(x-2) y=5/2x-8
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