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mars1129 [50]
3 years ago
11

HELPPPPPPPPPPPPPPPP ASAPPPP this is egit due todayyyyyy

Mathematics
1 answer:
Basile [38]3 years ago
3 0
The answer is 42m+12
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Line BC has an equation of a line Y equals 2X +3 and F has an equation of a line Y equals -1/2 x+4 these two equations represent
Masja [62]

Answer:

Lines BC and F represent perpendicular lines

Step-by-step explanation:

we have

<em>Line BC</em>

y=2x+3

the slope of the line BC is m=2

<em>Line F</em>

y=-(1/2)x+4

the slope of the line F is m=-1/2

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

m1*m2=-1

we have

m1=2 -----> slope line BC

m2=-1/2 -----> slope line F

Find the product of their slopes

(2)(-1/2)=-1

therefore

Lines BC and F represent perpendicular lines

6 0
3 years ago
How would I solve for x?​
vaieri [72.5K]

Answer:

x = 65

Step-by-step explanation:

First, we calculate the unknown angle of the left triangle and right triangle:180 - 62 - 50 = 68

Unknown angle for left triangle⬆️

180 - 80 - 53 = 47

Unknown angle for right triangle⬆️

Now we've calculated the two angles for the small triangle in the middle. So, we just have to calculate the top angle of the middle triangle:

180 - 68 - 47 = 65

The angle 65° and angle of x are vertical angle.(both are equal)

So... <u>x= 65°</u>

<em>hope it </em><em>helps </em><em>:</em><em>)</em>

4 0
3 years ago
Find the value of tan(B)<br><br> please help quickly
elena55 [62]

Answer:

it is 4/3

Step-by-step explanation:

because tan(B) = opposite/adjacent

4 0
3 years ago
There are 20 girls and 26 boys on the tennis team.
salantis [7]

Answer:

B 1013

Step-by-step explanation:

because 20/2 is 10 and 26/2 is 13 so 1013

6 0
3 years ago
Read 2 more answers
A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.
Crank

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean(\mu) = 500 and a standard deviation(\sigma) =  100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = \dfrac{Y-\mu}{\sigma}

Z-score = \dfrac{625-500}{100}

⇒ Z-score = \dfrac{125}{100}

⇒Z-score =1.25

Therefore , the required z-score = 1.25

6 0
3 years ago
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