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3 years ago

HELPPPPPPPPPPPPPPPP ASAPPPP this is egit due todayyyyyy

Mathematics

1 answer:

Basile [38]3 years ago

3 0

The answer is 42m+12

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A local board of education conducted a survey of residents in the community concerning a property tax levy on the coming local b

statuscvo [17]

Answer: B. 0.4542 to 0.5105.

Step-by-step explanation:

The confidence interval for population proportion is given by :-

$\hat{p}\pm z^* \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = Sample proportion.

n= sample size.

z* = Critical value.

Let p represent the proportion of residents in the community that support the property tax levy.

As per given , we have

Of the 850 residents surveyed, 410 supported the property tax levy.

i.e. n= 850 , $\hat{p}=\dfrac{410}{850}=0.48235$

From z-table , the critical value corresponds to 90% confidence level = z*=1.645

Now, 90% confidence interval for p:

$=0.48235\pm (1.645)\sqrt{\dfrac{0.48235(1-0.48235)}{850}}$

$=0.48235\pm (1.645)\sqrt{0.00029375115}$

$=0.48235\pm (1.645)(0.017139170049)$

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$=(0.48235-0.0281939,\ 0.48235+ 0.0281939)\\\\=(0.4541561,\ 0.5105439)\\\\\approx(0.4542,\ 0.5105)$

Hence, the correct answer is B. 0.4542 to 0.5105.

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