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chubhunter [2.5K]
3 years ago
8

El administrador de una cafetería sabe que vende diariamente 50 litros de jugo mixto. Para elaborar este jugo se emplean dos pre

parados: uno de jugo de naranja, que contiene un 5% de jugo natural y otro preparado de jugo de toronja, que contiene 25% de jugo natural. Si se desea que el jugo mixto contenga un 10% de jugo natural, ¿Cuántos litros de cada preparado se deben emplear?
Mathematics
1 answer:
Strike441 [17]3 years ago
5 0

Answer:

<em>El administrador debe usar 37.5 litros de jugo al 5% y 12.5 litros de jugo al 25%.</em>

Step-by-step explanation:

<u>Sistemas de Ecuaciones</u>

Llamamos:

x = litros de jugo al 5% natural

y = litros de jugo al 25% natural

El administrador de la cafetería desea hacer 50 litros de jugo, luego:

x + y = 50                   [1]

Esos 50 litros de jugo deben tener 10% de jugo natural. Como cada parte de x aporta 5% y cada parte de y aporta 25%:

5x + 25y = 10*50 = 500

Dividimos entre 5:

x + 5y = 100             [2]

Restamos [2] menos [1]:

4y = 50

y = 50/4 = 12.5

De [1] tenemos que:

x = 50 - y = 50 - 12.5 = 37.5

El administrador debe usar 37.5 litros de jugo al 5% y 12.5 litros de jugo al 25%.

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In the question, we are informed that the equation of the line of best fit, for the, scatter plot with x representing the number of ice cubes and y representing the milliliters of juice is given as y =  -29.202x + 293.5.

We are asked to tell how many milliliters of juice will be in a glass with 7 ice cubes based on the line of best fit.

To find the milliliters of juice in the glass with 7 ice cubes, we substitute x = 7, in the equation of the line of best fit, to get a value of y, representing the milliliters of juice in the glass.

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Thus, the glass will contain <u>89.086 milliliters</u> of juice with 7 ice cubes, using the equation of the line of best fit, y =  -29.202x + 293.5.

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Answer:

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